Answer:
When cancelled
(1)^-9 ×(1)^-11=(95/25)^p.
SO, - 9+(-11) = p. [BY FORMULA a^m×a^n
- 9-11 = p. =a^m+n]
- 20=p
MARK ME BRAINLIEST ^_^
answer is in attachment
above answer is incorrect because it is same but in bracket and there powers are different
and according to BODMAS bracket is solved first
Step-by-step explanation:
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Answers & Comments
Answer:
When cancelled
(1)^-9 ×(1)^-11=(95/25)^p.
SO, - 9+(-11) = p. [BY FORMULA a^m×a^n
- 9-11 = p. =a^m+n]
- 20=p
MARK ME BRAINLIEST ^_^
Answer:
answer is in attachment
above answer is incorrect because it is same but in bracket and there powers are different
and according to BODMAS bracket is solved first
Step-by-step explanation:
Hope this helps you
Mark me as brainlist please