Explanation:

[tex] \frac{x - 2}{3} = \frac{y - 1}{4} = \frac{z + 3}{ - 5} [/tex]

The required plane passing through the points

ã= 2ī+2j+k and b= ī-2j+3k

And parallel to c=-3í+4j-5k

Parametric form of vector equation r = a+s(b−ā) + tē

Parametric form of vector equation r = a+s(b−ā) + tēř = (2ï + 2j + k) + s(i −4}+2k)

Parametric form of vector equation r = a+s(b−ā) + tēř = (2ï + 2j + k) + s(i −4}+2k)+1(-37 +47-5k), s, te R

Are nahi any other guesses

Answer:

parametric form of vector equation and cartesian equation of the plane passing through the point (2, 2,1) (1, -2,3) and parallel to the straight line passing through the point (2,1,-3) and (-1,5,-8)

Explanation:

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