Answer:
[tex](1) = p(y) = y { }^{2} - y + 1 \\ = put \: p = 0 \\ = (0) {}^{2} - 0 + 1 \\ = 1 \: answer[/tex]
Step-by-step explanation:
Hope you get your answer
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Answer:
[tex](1) = p(y) = y { }^{2} - y + 1 \\ = put \: p = 0 \\ = (0) {}^{2} - 0 + 1 \\ = 1 \: answer[/tex]
Verified answer
Step-by-step explanation:
Hope you get your answer