(10011001)2 = (153)10
Step by step solution
Step 1: Write down the binary number:
10011001
Step 2: Multiply each digit of the binary number by the corresponding power of two:
1x27 + 0x26 + 0x25 + 1x24 + 1x23 + 0x22 + 0x21 + 1x20
Step 3: Solve the powers:
1x128 + 0x64 + 0x32 + 1x16 + 1x8 + 0x4 + 0x2 + 1x1 = 128 + 0 + 0 + 16 + 8 + 0 + 0 + 1
Step 4: Add up the numbers written above:
128 + 0 + 0 + 16 + 8 + 0 + 0 + 1 = 153.
So, 153 is the decimal equivalent of the binary number 10011001.
Answer:
decimal number which is represented as (10011001) base 2
[tex] {2}^{7} + {2}^{4} + {2}^{3} + {2}^{0} \\ 128 + 16 + 8 + 1 \\ = 128 + 25 \\ = 153 [/tex]
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Answers & Comments
(10011001)2 = (153)10
Step by step solution
Step 1: Write down the binary number:
10011001
Step 2: Multiply each digit of the binary number by the corresponding power of two:
1x27 + 0x26 + 0x25 + 1x24 + 1x23 + 0x22 + 0x21 + 1x20
Step 3: Solve the powers:
1x128 + 0x64 + 0x32 + 1x16 + 1x8 + 0x4 + 0x2 + 1x1 = 128 + 0 + 0 + 16 + 8 + 0 + 0 + 1
Step 4: Add up the numbers written above:
128 + 0 + 0 + 16 + 8 + 0 + 0 + 1 = 153.
So, 153 is the decimal equivalent of the binary number 10011001.
Answer:
decimal number which is represented as (10011001) base 2
[tex] {2}^{7} + {2}^{4} + {2}^{3} + {2}^{0} \\ 128 + 16 + 8 + 1 \\ = 128 + 25 \\ = 153 [/tex]