find mass of h atoms present in 32g methane
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So, in 32g of methane, there will be
32g⋅14=8g of hydrogen
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Molar mass of CH4 (methane) is 16g
16g of methane contains 4moles of H atoms.
So, 32g of methane will contain 8 moles of H atoms.
8moles = 8×NA atoms of H
Molar mass of H2O is 18g
2moles of H is present in 18g of H2O
So 8 moles of H will be present in (18 × 4=) 72g of H2O.
Therefore, 72g of H2O will contain same number of H atoms as present in 32g of CH4.