Answer:

Then, k+2 = a1 + d and 3k-11 = a1 + 2d

So, k+2 = 5k-3+d and 3k-11 = 5k-3+2d

Simplify to get the following system of equations:

4k+d = 5

2k+2d = -8

Divide the second equation by -2: 4k+d = 5

-k-d = 4

Add the equations to obtain 3k = 9

k = 3

Step-by-step explanation: