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YashtheINDIAN
@YashtheINDIAN
August 2021
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Find K...... ......help to solve
Answers & Comments
arjun6068
Given,
Kx2+1-2(k-1)x+x2
=x2(k+1)-2(k-1)+1
Here,
a=(k+1)
b=-2(k-1) & c=1
for real and equal roots,
d=0=b2-4ac=0
putting the values of a,b,c
[-2(k-1)]2-4(k+1)(1)=0
Then on opening the brackets we’ll get,
(4k)(k-3)=0
= 4k=0 and (k-3)=0
= k=0 or k=3
ℍᝪℙℰ ⅈᝨ ℍℰℒℙՏ
ℽᝪႮ
0 votes
Thanks 2
arjun6068
did u like ??
YashtheINDIAN
yes
arjun6068
mm
arjun6068
ok
arjun6068
tnks for following me....i am following u bro
YashtheINDIAN
OK cool thanks Byy
arjun6068
byy
arjun6068
gud nite
usjadhav2001
Answer:
ok
0,3
ok
thank you
ans
ok
bukja
0 votes
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Answers & Comments
Kx2+1-2(k-1)x+x2
=x2(k+1)-2(k-1)+1
Here,
a=(k+1)
b=-2(k-1) & c=1
for real and equal roots,
d=0=b2-4ac=0
putting the values of a,b,c
[-2(k-1)]2-4(k+1)(1)=0
Then on opening the brackets we’ll get,
(4k)(k-3)=0
= 4k=0 and (k-3)=0
= k=0 or k=3
ℍᝪℙℰ ⅈᝨ ℍℰℒℙՏ
ℽᝪႮ
Answer:
ok
0,3
ok
thank you
ans
ok
bukja