Answer:
0.3 units
Explanation:
3x+4y+7 = 0
Multiply with 2
6x+8y+14=0 ---> (1)
Given, 6x+8y+11=0 ----> (2)
If you compare with ax+by+c = 0,
a,b values for both equations are same
So, these two lines are parallel
a=6, b=8, c1=14, c2 = 11
Distance between two parallel lines = |c1-c2|÷√(a²+b²)
distance = |14-11|÷√(6²+8²)
= |3|÷√(36+64)
= 3÷√100
= 3/10
distance = 0.3 units
[tex] \frac{18}{13} units \: is \: the \: answer[/tex]
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Answers & Comments
Answer:
0.3 units
Explanation:
3x+4y+7 = 0
Multiply with 2
6x+8y+14=0 ---> (1)
Given, 6x+8y+11=0 ----> (2)
If you compare with ax+by+c = 0,
a,b values for both equations are same
So, these two lines are parallel
a=6, b=8, c1=14, c2 = 11
Distance between two parallel lines = |c1-c2|÷√(a²+b²)
distance = |14-11|÷√(6²+8²)
= |3|÷√(36+64)
= 3÷√100
= 3/10
distance = 0.3 units
Verified answer
[tex] \frac{18}{13} units \: is \: the \: answer[/tex]