Answer:
Given f(x)=x²-2x is a quadratic polynomial . It has only two zeroes.
Let f(x)=0.
So, x²-2x=0.
=> x(x-2)=0.
=> x = 0 Or x-2 = 0.
=> x=0 Or x=2.
0, 2 are zeroes of the polyomial f(x)
so therefore the zeros of the polynomials are 0,2
Step-by-step explanation:
P(x) = [tex]x^{2} -2x[/tex]
Now find such values for x such as
P(x) = 0
P(0) = 0 - 2(0) = 0
P(2) = 4 - 2*2 = 0
There are no more zeros of this polynomial
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Answers & Comments
Answer:
Given f(x)=x²-2x is a quadratic polynomial . It has only two zeroes.
Let f(x)=0.
So, x²-2x=0.
=> x(x-2)=0.
=> x = 0 Or x-2 = 0.
=> x=0 Or x=2.
0, 2 are zeroes of the polyomial f(x)
Answer:
so therefore the zeros of the polynomials are 0,2
Step-by-step explanation:
P(x) = [tex]x^{2} -2x[/tex]
Now find such values for x such as
P(x) = 0
P(0) = 0 - 2(0) = 0
P(2) = 4 - 2*2 = 0
There are no more zeros of this polynomial
so therefore the zeros of the polynomials are 0,2