Answer:
if√2and -√2 are two zeroes, then two factors are x-√2 and x+√2
product of these two factors=x^2-2
(2x^4-3x^3-3x^2+6x-2)÷(x^2-2)=
2x^2-3x+1
factorize this you will get
(x-1)(2x-1)
x-1=0 and 2x-1=0
x=1 and x=1/2
This polynomial has degree four, so there will be four zeroes and they are
√2, -√2, 1 and 1/2
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Answers & Comments
Answer:
if√2and -√2 are two zeroes, then two factors are x-√2 and x+√2
product of these two factors=x^2-2
(2x^4-3x^3-3x^2+6x-2)÷(x^2-2)=
2x^2-3x+1
factorize this you will get
(x-1)(2x-1)
x-1=0 and 2x-1=0
x=1 and x=1/2
This polynomial has degree four, so there will be four zeroes and they are
√2, -√2, 1 and 1/2