Answer:
Step-by-step explanation:
Let the zeroes of the quadratic polynomial be
α = √2
β =
Then, α + β =
αβ =
Sum of zeroes = α + β =
Product of zeroes = αβ = - 3
Then, the quadratic polynomial:
= x² - ( sum of zeroes) x + product of zeroes
Hope this helps : )
Mark as brainliest if you are satisfied.
= 1 + 2 + 3 + 4 + 5
= 3 + 3 + 4 + 5
= 6 + 4 + 5
= 10 + 5
= 15
Hope, it's help you.
✌️✌️
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Answers & Comments
Answer:
Step-by-step explanation:
Let the zeroes of the quadratic polynomial be
α = √2
β =![\frac{ - 3}{ \sqrt{2} } \frac{ - 3}{ \sqrt{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%203%7D%7B%20%5Csqrt%7B2%7D%20%7D%20)
Then, α + β =![\sqrt{2} + ( \frac{ - 3}{ \sqrt{2} } ) = \sqrt{2 } - \frac{3}{ \sqrt{2} } = \frac{2 - 3}{ \sqrt{2} } = \frac{ - 1}{ \sqrt{2} } \sqrt{2} + ( \frac{ - 3}{ \sqrt{2} } ) = \sqrt{2 } - \frac{3}{ \sqrt{2} } = \frac{2 - 3}{ \sqrt{2} } = \frac{ - 1}{ \sqrt{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%20%2B%20%28%20%5Cfrac%7B%20-%203%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%29%20%3D%20%20%5Csqrt%7B2%20%7D%20%20-%20%20%5Cfrac%7B3%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%20%3D%20%20%5Cfrac%7B2%20-%203%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%20%3D%20%20%5Cfrac%7B%20-%201%7D%7B%20%5Csqrt%7B2%7D%20%7D)
αβ =![\sqrt{2 } \times \frac{ - 3}{ \sqrt{2} } = - 3 \sqrt{2 } \times \frac{ - 3}{ \sqrt{2} } = - 3](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20-%203%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%20%3D%20%20-%203)
Sum of zeroes = α + β =![\frac{ - 1}{ \sqrt{2} } \frac{ - 1}{ \sqrt{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%201%7D%7B%20%5Csqrt%7B2%7D%20%7D%20)
Product of zeroes = αβ = - 3
Then, the quadratic polynomial:
= x² - ( sum of zeroes) x + product of zeroes
Hope this helps : )
Mark as brainliest if you are satisfied.
Step-by-step explanation:
= 1 + 2 + 3 + 4 + 5
= 3 + 3 + 4 + 5
= 6 + 4 + 5
= 10 + 5
= 15
Hope, it's help you.
✌️✌️