find 2 numbers in the ratio 8:7such that when each is decreased by 12 and a half they are in the ratio 11:9
pls fast
Answers & Comments
myselfyiri
Hey, Let the numbers be X and y, So, x/y=8/7 7x-8y=0-> first equation
Now, second equation, x-12/y-12=11/19 19(x-12)=11(y-12) 19x-209=11y-132 19x-11y=77.
So, in the first equation, 7x-8y=0 x=8y/7. Now, substitute X's value in equation second, 19(8y/7)-11y=77 152y/7-11y=77 75y/7=77 y=7*77/75 y=7.19. And,x=8y/7 x=8*7.19/7 x=8.22.
Hope this helps you buddy!! PLZ MARK AS BRAINLEST PLZ!!!!!! HAVE A NICE DAY :-):-)
3 votes Thanks 2
myselfyiri
oh yeah.. plz correct it n rest concept is correct
Answers & Comments
Let the numbers be X and y,
So, x/y=8/7
7x-8y=0-> first equation
Now, second equation,
x-12/y-12=11/19
19(x-12)=11(y-12)
19x-209=11y-132
19x-11y=77.
So, in the first equation,
7x-8y=0
x=8y/7.
Now, substitute X's value in equation second,
19(8y/7)-11y=77
152y/7-11y=77
75y/7=77
y=7*77/75
y=7.19.
And,x=8y/7
x=8*7.19/7
x=8.22.
Hope this helps you buddy!!
PLZ MARK AS BRAINLEST PLZ!!!!!!
HAVE A NICE DAY :-):-)