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Sandy260
@Sandy260
June 2021
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Factorise4(2a+b)^2 - (a-b)^2
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netradubal02
4 is 2 power 2
So [2(2a+b)]^2-(a-b)^2
Now you can use the identity a2-b2=(a+b)(a-b)
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mysticd
Hi ,
*******************************
We know the algebraic identity
x² - y² = ( x + y ) ( x - y )
************************************
4 ( 2a + b )² - ( a - b )²
= [ 2( 2a + b ]² - ( a - b )²
= ( 4a + b )² - ( a - b )²
= [ 4a + b + a - b ] [ ( 4a + b ) - ( a - b ) ]
= ( 5a ) ( 4a + b - a + b )
= 5a ( 3a + 2b )
I hope this helps you.
:)
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Answers & Comments
So [2(2a+b)]^2-(a-b)^2
Now you can use the identity a2-b2=(a+b)(a-b)
*******************************
We know the algebraic identity
x² - y² = ( x + y ) ( x - y )
************************************
4 ( 2a + b )² - ( a - b )²
= [ 2( 2a + b ]² - ( a - b )²
= ( 4a + b )² - ( a - b )²
= [ 4a + b + a - b ] [ ( 4a + b ) - ( a - b ) ]
= ( 5a ) ( 4a + b - a + b )
= 5a ( 3a + 2b )
I hope this helps you.
:)