Answer: x4–3x2+2
=x4−x3+x3−x2–2x2+2
=x3(x−1)+x2(x−1)−2(x2–1)
=x3(x−1)+x2(x−1)−2(x+1)(x−1)
=(x−1){x3+x2–2(x+1)}
=(x−1)(x3+x2–2x−2)
Answer: x⁴-3x²+2
put x²= y
then our new equation will be
y²-3y+2
by splitting we get
y²-2y-y+2
y(y-2)-1(y-2)
(y-1)(y-2)
now re substitute
(x²-1)(x²-2)
here is your factor
Explanation: hope it helps
please mark me as brainliest
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer: x4–3x2+2
=x4−x3+x3−x2–2x2+2
=x3(x−1)+x2(x−1)−2(x2–1)
=x3(x−1)+x2(x−1)−2(x+1)(x−1)
=(x−1){x3+x2–2(x+1)}
=(x−1)(x3+x2–2x−2)
Answer: x⁴-3x²+2
put x²= y
then our new equation will be
y²-3y+2
by splitting we get
y²-2y-y+2
y(y-2)-1(y-2)
(y-1)(y-2)
now re substitute
(x²-1)(x²-2)
here is your factor
Explanation: hope it helps
please mark me as brainliest