Step-by-step explanation:
81x2−225y281x2-225y2
Factor 99 out of 81x2−225y281x2-225y2.
Factor 99 out of 81x281x2.
9(9x2)−225y29(9x2)-225y2
Factor 99 out of −225y2-225y2.
9(9x2)+9(−25y2)9(9x2)+9(-25y2)
Factor 99 out of 9(9x2)+9(−25y2)9(9x2)+9(-25y2).
9(9x2−25y2)9(9x2-25y2)
Rewrite 9x29x2 as (3x)2(3x)2.
9((3x)2−25y2)9((3x)2-25y2)
Rewrite 25y225y2 as (5y)2(5y)2.
9((3x)2−(5y)2)9((3x)2-(5y)2)
Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=3xa=3x and
Answer:
(9x + 15y)(9x - 15y). Answer
Following this identity:
[tex](x + y)(x - y) = {x}^{2} - {y}^{2} [/tex]
Here,
81x^2 - 225y^2,
9x - 15y
(9x + 15y)(9x - 15y)
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Answers & Comments
Step-by-step explanation:
81x2−225y281x2-225y2
Factor 99 out of 81x2−225y281x2-225y2.
Factor 99 out of 81x281x2.
9(9x2)−225y29(9x2)-225y2
Factor 99 out of −225y2-225y2.
9(9x2)+9(−25y2)9(9x2)+9(-25y2)
Factor 99 out of 9(9x2)+9(−25y2)9(9x2)+9(-25y2).
9(9x2−25y2)9(9x2-25y2)
Rewrite 9x29x2 as (3x)2(3x)2.
9((3x)2−25y2)9((3x)2-25y2)
Rewrite 25y225y2 as (5y)2(5y)2.
9((3x)2−(5y)2)9((3x)2-(5y)2)
Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=3xa=3x and
Verified answer
Answer:
(9x + 15y)(9x - 15y). Answer
Step-by-step explanation:
Following this identity:
[tex](x + y)(x - y) = {x}^{2} - {y}^{2} [/tex]
Here,
81x^2 - 225y^2,
9x - 15y
(9x + 15y)(9x - 15y)
Please Mark me Brainliest