Answer:
(4+a+b)(4−a−b
∴ 16-a^2-2ab-b^216−a
2
−2ab−b
=4^2-(a^2+2ab+b^2)=4
−(a
+2ab+b
)
=4^2-(a+b)^2=4
−(a+b)
Using algebraic identity,
(x+y)^2=x^2+2xy+y^2(x+y)
=x
+2xy+y
=[4+(a+b)][4-(a+b)]=[4+(a+b)][4−(a+b)]
x^2-y^{2} =(x+y)(x-y)x
−y
=(x+y)(x−y)
=(4+a+b)(4-a-b)=(4+a+b)(4−a−b)
Hence, the factorisation of 16-a^2-2ab-b^2=(4+a+b)(4-a-b)16−a
=(4+a+b)(4−a−b)
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
(4+a+b)(4−a−b
∴ 16-a^2-2ab-b^216−a
2
−2ab−b
2
=4^2-(a^2+2ab+b^2)=4
2
−(a
2
+2ab+b
2
)
=4^2-(a+b)^2=4
2
−(a+b)
2
Using algebraic identity,
(x+y)^2=x^2+2xy+y^2(x+y)
2
=x
2
+2xy+y
2
=[4+(a+b)][4-(a+b)]=[4+(a+b)][4−(a+b)]
Using algebraic identity,
x^2-y^{2} =(x+y)(x-y)x
2
−y
2
=(x+y)(x−y)
=(4+a+b)(4-a-b)=(4+a+b)(4−a−b)
Hence, the factorisation of 16-a^2-2ab-b^2=(4+a+b)(4-a-b)16−a
2
−2ab−b
2
=(4+a+b)(4−a−b)