Answer:
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[tex] {x}^{2} + 8x + 16 \\ {x}^{2} + 4x + 4x + 16 \\ x(x + 4) + 4(x + 4) \\ (x + 4)(x + 4) \\ \boxed{ = {(x + 4)}^{2} }[/tex]
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Answer:
I hope this answer was helpful.
[tex] {x}^{2} + 8x + 16 \\ {x}^{2} + 4x + 4x + 16 \\ x(x + 4) + 4(x + 4) \\ (x + 4)(x + 4) \\ \boxed{ = {(x + 4)}^{2} }[/tex]