Answer:

❍ \rm \bf{Option (b),}Option(b), \boxed{\tt{\red{6\sqrt{6}\: m^{2}}}}66m2

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Gɪᴠᴇɴ :-

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\begin{gathered}\begin{gathered} ❍ \:\rm \bf Sides \begin{cases} & \rm{a = {5\:m}} \\ & \rm{b = {6\:m}} \\ & \rm{c = {7\:m}} \end{cases} \\\end{gathered}\end{gathered}❍Sides⎩⎪⎪⎨⎪⎪⎧a=5mb=6mc=7m

Tᴏ Fɪɴᴅ :-

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❍ Area of the triangle (∆).

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Fᴏʀᴍᴜʟᴀ :-

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❍ \boxed{\sf{\green{∆=\sqrt{s(s-a)(s-b)(s-c)}}}}∆=s(s−a)(s−b)(s−c)

Where, \sf \bf {\:s = \dfrac{a+b+c}{2}}s=2a+b+c

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Sᴏʟᴜᴛɪᴏɴ :-

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➪ \sf{\purple{s = \dfrac{a+b+c}{2}}}s=2a+b+c

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➪ \sf{\purple{s = \dfrac{5+6+7}{2}}}s=25+6+7

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➪ \sf{\purple{s = \dfrac{18}{2} = 9m}}s=218=9m

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➪ \sf{\pink{∆=\sqrt{s(s-a)(s-b)(s-c)}}}∆=s(s−a)(s−b)(s−c)

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➪ \sf{\pink{∆=\sqrt{9(9-5)(9-6)(9-7)}}}∆=9(9−5)(9−6)(9−7)

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➪ \sf{\pink{∆=\sqrt{9(4)(3)(2)}}}∆=9(4)(3)(2)

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➪ \sf{\red{∆=\sqrt{36\times 6}}}∆=36×6

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➪ \sf{\pink{∆=}}∆= {\bf{\orange{6\sqrt{6} \:m^2}}}66m2

not Abe to understand the question could you post the snapshot of the question