Given expression is 6ab−b2 +12ac−2bc
It can be written as 6ab−b 2+12ac−2bc=b(6a−b+2c(6a−b)=(b+2c)(6a−b)
Solution:
[tex]6ab - b {}^{2} + 12ac - 2bc[/tex]
[tex]6ab + 12ac - b {}^{2} - 2bc[/tex]
[tex] = 6a(b + 2c) - b(b + 2c)[/tex]
[tex] = (b + 2c)(6a - b) \: \: ans.[/tex]
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Given expression is 6ab−b2 +12ac−2bc
It can be written as 6ab−b 2+12ac−2bc=b(6a−b+2c(6a−b)=(b+2c)(6a−b)
Thus factors are,(b+2c),(6a−b).
Verified answer
Solution:
[tex]6ab - b {}^{2} + 12ac - 2bc[/tex]
[tex]6ab + 12ac - b {}^{2} - 2bc[/tex]
[tex] = 6a(b + 2c) - b(b + 2c)[/tex]
[tex] = (b + 2c)(6a - b) \: \: ans.[/tex]