Given a quadratic in the form \(ax^{2}+bx+c\) , find two numbers that, when multiplied together, equal \(ac\) ; and, when added together, equal \(b\) . Decompose the middle term to include your two factors.\(2x^{2}+\textcolor{#C58AF9}{5x}-12\)\(2x^{2}+\textcolor{#C58AF9}{8x}\textcolor{#C58AF9}{-3x}-12\)
(2x−3)(x+4)open paren 2 x minus 3 close paren open paren x plus 4 close paren\((2x-3)(x+4)\)
\(2x(x+4)-3(x+4)\)\((2x-3)(x+4)\)
(2x−3)(x+4)open paren 2 x minus 3 close paren open paren x plus 4 close paren\((2x-3)(x+4)\)
Answers & Comments
Step-by-step explanation:
2x²+(2+3)x-12
2x²+2x-3x-12
2x(x+1)-3(x+4)
(x+1)(x+4)ans.
please mark me a brainliest
Answer: (2x-3)(x+4)
Step-by-step explanation:
Given a quadratic in the form \(ax^{2}+bx+c\) , find two numbers that, when multiplied together, equal \(ac\) ; and, when added together, equal \(b\) . Decompose the middle term to include your two factors.\(2x^{2}+\textcolor{#C58AF9}{5x}-12\)\(2x^{2}+\textcolor{#C58AF9}{8x}\textcolor{#C58AF9}{-3x}-12\)
(2x−3)(x+4)open paren 2 x minus 3 close paren open paren x plus 4 close paren\((2x-3)(x+4)\)
\(2x(x+4)-3(x+4)\)\((2x-3)(x+4)\)
(2x−3)(x+4)open paren 2 x minus 3 close paren open paren x plus 4 close paren\((2x-3)(x+4)\)