Answer:
16(2p−3q)^2 −4(2p−3q)
=4(2p−3q) [4(2p−3q)−1]
take 4(2p-3q) common,
=4(2p−3q)(8p−12q−1)
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Answer:
16(2p−3q)^2 −4(2p−3q)
=4(2p−3q) [4(2p−3q)−1]
take 4(2p-3q) common,
=4(2p−3q)(8p−12q−1)