Answer:
(x-3)²
We know that (x-y)² = x² - 2xy + y²
We can get the square root of the two opposties: x for x², 3 for 9
So we're left with (x-3)²
(x-3)² = x² - 2x(3) + 9
(x-3)² = x²- 6x + 9
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Answer:
(x-3)²
We know that (x-y)² = x² - 2xy + y²
We can get the square root of the two opposties: x for x², 3 for 9
So we're left with (x-3)²
(x-3)² = x² - 2x(3) + 9
(x-3)² = x²- 6x + 9