Answer:
Consider the ΔPQR. ∠PRS is the exterior angle and ∠QPR and ∠PQR are interior angles.
So, ∠PRS = ∠QPR+∠PQR (According to triangle property)
Or, ∠PRS -∠PQR = ∠QPR ———–(i)
Now, consider the ΔQRT,
∠TRS = ∠TQR+∠QTR
Or, ∠QTR = ∠TRS-∠TQR
We know that QT and RT bisect ∠PQR and ∠PRS respectively.
So, ∠PRS = 2 ∠TRS and ∠PQR = 2∠TQR
Now, ∠QTR = ½ ∠PRS – ½∠PQR
Or, ∠QTR = ½ (∠PRS -∠PQR)
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your intro army.
Explanation:
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Verified answer
Answer:
Consider the ΔPQR. ∠PRS is the exterior angle and ∠QPR and ∠PQR are interior angles.
So, ∠PRS = ∠QPR+∠PQR (According to triangle property)
Or, ∠PRS -∠PQR = ∠QPR ———–(i)
Now, consider the ΔQRT,
∠TRS = ∠TQR+∠QTR
Or, ∠QTR = ∠TRS-∠TQR
We know that QT and RT bisect ∠PQR and ∠PRS respectively.
So, ∠PRS = 2 ∠TRS and ∠PQR = 2∠TQR
Now, ∠QTR = ½ ∠PRS – ½∠PQR
Or, ∠QTR = ½ (∠PRS -∠PQR)
hi
I am Sargun class 9
your intro army.
Explanation:
hope it helps u
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