A. (x–5+x²–1) (x) = x³+x²-6x
B. (x—5–x²–1) (x) = –x³+x²-6x
C. (x–5 • x²–1) (x) = —5x³+ x²–x
D. (x–5 / x² –1) (x) = x³–x²–5 / x
E. x²–1/x–5 (x) = x³–5x –1
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Answers & Comments
A. (x–5+x²–1) (x) = x³+x²-6x
B. (x—5–x²–1) (x) = –x³+x²-6x
C. (x–5 • x²–1) (x) = —5x³+ x²–x
D. (x–5 / x² –1) (x) = x³–x²–5 / x
E. x²–1/x–5 (x) = x³–5x –1
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