f (a) = 2a + 1 and g(a) = a3 − 2a, find: (f

Answer:+4a+1Step-by-step explanation:f(a) = 2a+1g(a) = (f-g)a = (2a+1) - ()=+4a+1

Answer:

$a^{3}$ +4a+1

Step-by-step explanation:

f(a) = 2a+1

g(a) = $a^{3}-2a$

(f-g)a = (2a+1) - ( $a^{3}-2a$ )

= $a^{3}$ +4a+1

$\huge \underline{\tt \green{f (a) = 2a + 1 and\ g(a) = a3 - 2a, find: (f - g) (a)}}$

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${ \large{ \underline{ \overline{ \boxed{ \blue{\mathbb { \: SOLUTION}}}}}}}$

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${ \large{ \underline{ \overline{ \boxed{ \blue{\mathbb { \: ANSWER}}}}}}}$

$\huge \underline{\tt \green{f(a) + g(a) = 5a -2}}$

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${\boxed{\boxed{\green{\mathbb{ LukeCha15 }}}}}$

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