Answer:
answer is
2:3:520%:30%:50%
please mark me as a brainleist
step by step solution:
Total part =2+3+5=10
Therefore, Fractional part 10/2 : 10/3 : 10/5
⇒ Percentage of parts = 10/2 ×100: 10/3 ×100: 10/5 ×100
⇒ Percentage of parts =20%:30%:50%
[tex]\large\underline{\sf{Solution-}}[/tex]
Given that, three parts are in the ratio 2 : 5 : 3.
So, total sum = 2 + 5 + 3 = 10.
Now,
The parts in term of percentages is evaluated as
[tex]\rm \: {1}^{st} \: part \: = \: \frac{2}{10} \times 100 \: \% \\ [/tex]
[tex]\rm \: {1}^{st} \: part \: = \:2 \times 10 \: \% \\ [/tex]
[tex]\bf\implies \: {1}^{st} \: part \: = \:20 \: \% \\ \\ [/tex]
Now, Consider
[tex]\rm \: {2}^{nd} \: part \: = \: \dfrac{5}{10} \times 100 \: \% \\ [/tex]
[tex]\rm \: {2}^{nd} \: part \: = \: 5 \times 10 \: \% \\ [/tex]
[tex]\bf\implies \: {2}^{nd} \: part \: = \: 50 \: \% \\ \\ [/tex]
[tex]\rm \: {3}^{rd} \: part \: = \: \dfrac{3}{10} \times 100 \: \% \\ [/tex]
[tex]\rm \: {3}^{rd} \: part \: = \: 3\times 10 \: \% \\ [/tex]
[tex]\bf\implies \: {3}^{rd} \: part \: = \: 30 \: \% \\ \\ [/tex]
[tex]\rule{190pt}{2pt}[/tex]
[tex] { \red{ \mathfrak{Additional\:Information}}}[/tex]
[tex] \begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain\%) or(100-Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}[/tex]
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Answers & Comments
Answer:
answer is
2:3:520%:30%:50%
please mark me as a brainleist
step by step solution:
Total part =2+3+5=10
Therefore, Fractional part 10/2 : 10/3 : 10/5
⇒ Percentage of parts = 10/2 ×100: 10/3 ×100: 10/5 ×100
⇒ Percentage of parts =20%:30%:50%
Verified answer
[tex]\large\underline{\sf{Solution-}}[/tex]
Given that, three parts are in the ratio 2 : 5 : 3.
So, total sum = 2 + 5 + 3 = 10.
Now,
The parts in term of percentages is evaluated as
[tex]\rm \: {1}^{st} \: part \: = \: \frac{2}{10} \times 100 \: \% \\ [/tex]
[tex]\rm \: {1}^{st} \: part \: = \:2 \times 10 \: \% \\ [/tex]
[tex]\bf\implies \: {1}^{st} \: part \: = \:20 \: \% \\ \\ [/tex]
Now, Consider
[tex]\rm \: {2}^{nd} \: part \: = \: \dfrac{5}{10} \times 100 \: \% \\ [/tex]
[tex]\rm \: {2}^{nd} \: part \: = \: 5 \times 10 \: \% \\ [/tex]
[tex]\bf\implies \: {2}^{nd} \: part \: = \: 50 \: \% \\ \\ [/tex]
Now, Consider
[tex]\rm \: {3}^{rd} \: part \: = \: \dfrac{3}{10} \times 100 \: \% \\ [/tex]
[tex]\rm \: {3}^{rd} \: part \: = \: 3\times 10 \: \% \\ [/tex]
[tex]\bf\implies \: {3}^{rd} \: part \: = \: 30 \: \% \\ \\ [/tex]
[tex]\rule{190pt}{2pt}[/tex]
[tex] { \red{ \mathfrak{Additional\:Information}}}[/tex]
[tex] \begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain\%) or(100-Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}[/tex]