Step-by-step explanation:
solution;
0.9 bar on on 9
No. before decimal + repeating number/ '9' as no. of times of repeating number
= 0+9/9
=9/9 = 1
Answer:
Let x=0.99999⋯ ...(1)
Multiply eq (1) by 10 we get
10x=9.9999⋯ ...(2)
Substract (1) from (2), we get
⇒9x=9
⇒x=
1
=1
Here,
p=1 and q=1
Thus,
0.9999⋯=1
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Answers & Comments
Step-by-step explanation:
solution;
0.9 bar on on 9
No. before decimal + repeating number/ '9' as no. of times of repeating number
= 0+9/9
=9/9 = 1
Verified answer
Answer:
Let x=0.99999⋯ ...(1)
Multiply eq (1) by 10 we get
10x=9.9999⋯ ...(2)
Substract (1) from (2), we get
⇒9x=9
⇒x=
1
1
=1
Here,
p=1 and q=1
Thus,
0.9999⋯=1