Explain how 2-chloro-3-methylbutane on treatment with alcoholic potash given 2-methyl but-2ene as
the major product.
Give proper and meaninful answer .
length of the answer shoulb be according to 2 marks.
the major product.
Give proper and meaninful answer .
length of the answer shoulb be according to 2 marks.
Add an Answer
More Questions From This User See All
Answers & Comments
Answer:
it is in the attachment given below.....
Hope u get it mate.....
The compound 2-chloro-3-methylbutane on treatment with alcoholic potash given 2-methyl but-2-ene in accordance with the Saytzeff rule.
- This reaction is termed as dehydrohalogenation.
- It is a β- elimination reaction.
- The chloride at 2- position is removed along with the hydrogen from the β- position according to the Saytzeff rule.
CH3-CH(Cl)-CH(CH3)-CH3 + alc. KOH → CH3-CH=C(CH3)-CH3 + HCl
- Hence, 2-methyl but-2-ene is formed as the major product.