Answer:
[tex]30-12\sqrt{6}[/tex]
Explanation:
I assume you mean [tex](3\sqrt{2}-2\sqrt{3})^2[/tex].
Then,
[tex](3\sqrt{2}-2\sqrt{3} )^{2}=(\sqrt{18}-\sqrt{12})^{2}[/tex] (expanding the square roots)
Using [tex](a-b)^{2}=a^{2}+b^{2}-2ab[/tex]
[tex](\sqrt{18}-\sqrt{12})^{2}=18+12-2*\sqrt{18}*\sqrt{12}=30-2*\sqrt{216}[/tex]
Which is equal to [tex]30-2*6\sqrt{6}=30-12\sqrt{6}[/tex]
I hope that the answer was helpful.
Have a great day.
30-12√3
do the {a-b}^2=a^2+b^2-2ab sum and u'll get this same answer
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Answers & Comments
Answer:
[tex]30-12\sqrt{6}[/tex]
Explanation:
I assume you mean [tex](3\sqrt{2}-2\sqrt{3})^2[/tex].
Then,
[tex](3\sqrt{2}-2\sqrt{3} )^{2}=(\sqrt{18}-\sqrt{12})^{2}[/tex] (expanding the square roots)
Using [tex](a-b)^{2}=a^{2}+b^{2}-2ab[/tex]
[tex](\sqrt{18}-\sqrt{12})^{2}=18+12-2*\sqrt{18}*\sqrt{12}=30-2*\sqrt{216}[/tex]
Which is equal to [tex]30-2*6\sqrt{6}=30-12\sqrt{6}[/tex]
I hope that the answer was helpful.
Have a great day.
Answer:
30-12√3
do the {a-b}^2=a^2+b^2-2ab sum and u'll get this same answer