Exercises:
1. The width of a rectangle card is 2 cm. less than the length. The area is 35 cm?. Find the
length and width.
2.A flowerbed is to be 3mthan it is wide.The flowerbed will have an area of 70m².What will its dimensions be?
3The length of a rectangle is the two feet less than 3 tomes the width.If the area is 65 ft²,find the dimension
pasagot pls yung tama po kailangan ko po kasi ehh
1. The width of a rectangle card is 2 cm. less than the length. The area is 35 cm?. Find the
length and width.
2.A flowerbed is to be 3mthan it is wide.The flowerbed will have an area of 70m².What will its dimensions be?
3The length of a rectangle is the two feet less than 3 tomes the width.If the area is 65 ft²,find the dimension
pasagot pls yung tama po kailangan ko po kasi ehh
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Answer:
1. L = 7 cm, W = 5 cm
2. L = 10 m, W = 7 m
3. L = 13 ft, W = 5 ft
Step-by-step explanation:
1. A = LW
W = L - 2
A = 35 cm²
Substitute the given to the formula, A = LW
35 cm² = (L)(L - 2)
35 = L² - 2L
L² - 2L - 35 = 0
To find the value of L, use the quadratic equation.
L = 7, -5
Choose 7 as the value of L since 5 is negative.
L = 7 cm
Therefore, W = L - 2
W = 7 - 2; W = 5 cm
checking: A = LW
35 cm² = (7 cm)(5 cm)
35 cm² = 35 cm²
*For 2 and 3, do the same procedure as number 1.
2. Use L = W + 3
3. Use L = 3W + 2
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