Exercises 3. Solve the following problems.
1. The distance an object falls from rest varies directly as the square of time. If an object falls
432 ft. in 6 seconds, how far will it fall in 10 seconds?
2. The resistance of a wire varies directly as the length and inversely as the diameter. If a wire
8.25 m long with a diameter of 0.10 m las a resistance of 4 ohms, what is the resistance of a
wire of the same material that is 16.75 m long and 0.12m in diameter.
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Answers & Comments
Let's first come up with some variables, and then perform an English-to-Math translation to derive an equation.
d - distance an object falls
t - the time it falls
Imagine the object in hand, and t is measured by a
stopwatch. The stopwatch starts at the moment the object is released; at this moment, t 0. d is also equal to 0 when t = 0, since at the precise moment it is released, it hasn't fallen yet.
Now that we have the situation and variables defined, we can begin the English-to-Math translation:
"The distance a free falling object falls" "is" "directly
proportional to" "the square of the time it falls".
D - kt²
We are also given a distance (d = 44) for a given time (t =
5). We can solve for k by substituting these values into:
Our equation:
44 = k (5²). Since 5² = 25,
44 = 25k. Divide both sides by 25:
44/25k
Hence our equation is complete:
d = (44/25) * t
"How far will it have fallen in 6 seconds" means, what is
d ift 6? This is equivalent to putting 6 in place of t:
d (44/25) * 6, or
d (44/25) * 36.
Final answer: D = 1200 ft.
( look at the picture attached )
#hopeithelps
I can't answer the 2nd question sorry.