Exercise C: Solve the following.
For items 1 and 2, have your final answer in terms of π.
1. A therapy pool in a water spa is in the shape of a 10-meter wide circle. How much material would it take to cover it?
2. The bottom of a circular swimming pool with a radius of 13 feet is made up of blue tiles. How many square feet is that?
For items 3 to 5, use 3.14 for π.
3. A circular clock with a radius of 6 inches is attached on the wall. How much area of the wall did it occupy?
4. What is the area of a circular skating rink that has a radius of 9m?
5. The top of a circular table is to be covered with a cloth. If the diameter of the table is 4 feet. How many square feet of cloth is needed for the table?
For items 1 and 2, have your final answer in terms of π.
1. A therapy pool in a water spa is in the shape of a 10-meter wide circle. How much material would it take to cover it?
2. The bottom of a circular swimming pool with a radius of 13 feet is made up of blue tiles. How many square feet is that?
For items 3 to 5, use 3.14 for π.
3. A circular clock with a radius of 6 inches is attached on the wall. How much area of the wall did it occupy?
4. What is the area of a circular skating rink that has a radius of 9m?
5. The top of a circular table is to be covered with a cloth. If the diameter of the table is 4 feet. How many square feet of cloth is needed for the table?
Add an Answer
More Questions From This User See All
Answers & Comments
Answer:
1. The area of the therapy pool is:
A = πr^2
A = π(5m)^2
A = 25π square meters
So, it would take 25π square meters of material to cover the pool.
2. The area of the bottom of the pool is:
A = πr^2
A = π(13ft)^2
A ≈ 530.93 square feet
So, the bottom of the pool made up of blue tiles has an area of approximately 530.93 square feet.
3. The area occupied by the clock on the wall is:
A = πr^2
A = π(6in)^2
A ≈ 113.1 square inches
So, the clock occupies approximately 113.1 square inches of the wall.
4. The area of the skating rink is:
A = πr^2
A = π(9m)^2
A ≈ 254.47 square meters
So, the area of the skating rink is approximately 254.47 square meters.
5. The area of the circular table is:
A = πr^2
A = π(2ft)^2
A ≈ 12.57 square feet
So, 12.57 square feet of cloth is needed to cover the table.