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Answer:

#1

a. P(A and B) = P(A) * P(B) = 0.47 * 0.33 = 0.1551

b. P(A or B) = P(A) + P(B) - P(A and B) = 0.47 + 0.33 - 0.1551 = 0.6449

c. P(not A and B) = P(B) - P(A and B) = 0.33 - 0.1551 = 0.1749

#2

The probability of drawing an Ace in the first draw is 4/52 (1/13) and the probability of drawing a heart in the second draw, given that an Ace was drawn in the first draw, is 12/52 (1/4). So, the total probability is (1/13) * (1/4) = 1/52 = 0.0192.

#3

The probability of getting a head in the first toss is 1/2 and the probability of getting a tail in the second toss, given that a head was obtained in the first toss, is 1/2. So, the total probability is (1/2) * (1/2) = 1/4 = 0.25.

Answer:

1. Given that P(A) is 0.47 and P(B) is 0.33 and event A and event B are independent events, find: a. P(An B) b. P(ANB) c. P(A'N B)

a. P(An B) = 0.409

b. P(ANB) = 0.132

c. P(A'N B) = 0.066

2. Two cards are drawn with replacement. What is the probability of drawing an Ace (4) in the first draw and a heart (H) in the second draw?

The probability of getting an Ace in the first draw and a Heart in the second draw would be = 0.1647

3. A coin is tossed two times. What is the probability of getting a head in the first toss and a tail in the second toss?​

1 - (1/2) ^ 2 = 0.75

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