Answer:

SOLUTION

1. fix) = 5x+1₂"X" can take any value. XE(-∞0, +00)

2. f(x)=x-7,"x" can take any value, XE(-00, 700)

3. f(x)=2x-2,"x" can take any value, XE (-∞0, +∞0)

4. x)= [X-10), X-1

(The denominator can't be "0")

So, x can't take" 1", XE (-∞0, 1) U (1, +∞)

5. f(x) = x² +2,"x" can take any value, XE(-∞, +∞0).

ANSWER

1. X = -15

1. X = -152. x = 7

1. X = -152. x = 73. x = 1

1. X = -152. x = 73. x = 14. x = 1

1. X = -152. x = 73. x = 14. x = 15. x = -1

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