Answer:
Relative density of silver =densityofwaterdensityofsilver
Density of silver = Rel. density of silver × density of water
Hence, from given data
=103×10.8 kgm−3
=10800kgm−3
Relative density of silver =
[tex] \frac{density \: of \: silver}{density \: of \: water} [/tex]
[tex]10 {}^{3} \times 10.8kgm {}^{ - 3} = [/tex]
[tex]10800kgm {}^{ - 3} [/tex]
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Answer:
Relative density of silver =densityofwaterdensityofsilver
Density of silver = Rel. density of silver × density of water
Hence, from given data
=103×10.8 kgm−3
=10800kgm−3
Verified answer
Relative density of silver =
[tex] \frac{density \: of \: silver}{density \: of \: water} [/tex]
Density of silver = Rel. density of silver × density of water
Hence, from given data
[tex]10 {}^{3} \times 10.8kgm {}^{ - 3} = [/tex]
[tex]10800kgm {}^{ - 3} [/tex]
plz make me brainliest ànswer..