Answer:
6
Step-by-step explanation:
3 and -3 will cut and leave -1
(5)-1 x (3/5)-2
3/5 will multiply by 2= -6/5
-5 x (-6/5)
-5 and 5 will cut and leave -1
- x - = +
-1 x (-6) = 6 answer
Ask more questions if you don't understand. We can help you.
[tex]\;[/tex]
Let's find the product of the two base numbers.
[tex]\text{$\Longrightarrow\dfrac{5}{3}\times \dfrac{3}{5}=1$}[/tex]
We know that both are reciprocal to one another because the product equals the number 1.
So, that means either [tex]\text{$\dfrac{5}{3}={\bigg(\dfrac{3}{5}\bigg)}^{-1}$ or $\dfrac{3}{5}={\bigg(\dfrac{5}{3}\bigg)}^{-1}$}[/tex].
Choose any one of two. I choose [tex]\text{$\dfrac{5}{3}={\bigg(\dfrac{3}{5}\bigg)}^{-1}$}[/tex].
[tex]\text{$\bigg\{{\bigg(\dfrac{5}{3}\bigg)}^{-1}\bigg\}^{-3}\times {\bigg(\dfrac{3}{5}\bigg)}^{-2}$}[/tex]
[tex]\text{$={\bigg(\dfrac{3}{5}\bigg)}^{3}\times {\bigg(\dfrac{3}{5}\bigg)}^{-2}$}[/tex]
[tex]\text{$={\bigg(\dfrac{3}{5}\bigg)}^{1}$}[/tex]
[tex]\text{$=\dfrac{3}{5}$}[/tex]
Hence the correct answer-
[tex]\boxed{{\bigg(\dfrac{5}{3}\bigg)}^{-3}\times {\bigg(\dfrac{3}{5}\bigg)}^{-2}=\dfrac{3}{5}}[/tex]
Happy learning!
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Answers & Comments
Answer:
6
Step-by-step explanation:
3 and -3 will cut and leave -1
(5)-1 x (3/5)-2
3/5 will multiply by 2= -6/5
-5 x (-6/5)
-5 and 5 will cut and leave -1
- x - = +
-1 x (-6) = 6 answer
Verified answer
Ask more questions if you don't understand. We can help you.
[tex]\;[/tex]
Let's find the product of the two base numbers.
[tex]\text{$\Longrightarrow\dfrac{5}{3}\times \dfrac{3}{5}=1$}[/tex]
We know that both are reciprocal to one another because the product equals the number 1.
So, that means either [tex]\text{$\dfrac{5}{3}={\bigg(\dfrac{3}{5}\bigg)}^{-1}$ or $\dfrac{3}{5}={\bigg(\dfrac{5}{3}\bigg)}^{-1}$}[/tex].
[tex]\;[/tex]
Choose any one of two. I choose [tex]\text{$\dfrac{5}{3}={\bigg(\dfrac{3}{5}\bigg)}^{-1}$}[/tex].
[tex]\text{$\bigg\{{\bigg(\dfrac{5}{3}\bigg)}^{-1}\bigg\}^{-3}\times {\bigg(\dfrac{3}{5}\bigg)}^{-2}$}[/tex]
[tex]\text{$={\bigg(\dfrac{3}{5}\bigg)}^{3}\times {\bigg(\dfrac{3}{5}\bigg)}^{-2}$}[/tex]
[tex]\text{$={\bigg(\dfrac{3}{5}\bigg)}^{1}$}[/tex]
[tex]\text{$=\dfrac{3}{5}$}[/tex]
[tex]\;[/tex]
Hence the correct answer-
[tex]\boxed{{\bigg(\dfrac{5}{3}\bigg)}^{-3}\times {\bigg(\dfrac{3}{5}\bigg)}^{-2}=\dfrac{3}{5}}[/tex]
[tex]\;[/tex]
Happy learning!