Answer:
1. m + 5q = 26
2. (y - x)^2 = 4
Step-by-step explanation:
Just substitute
1. m + 5q, where m = 1 and q = 5
m + 5q = 1 + (5*5)
m + 5q = 1 + 25
m + 5q = 26
for number 2, you need to simplify it first then substitute or directly substitute it
LONG METHOD:
(y - x)^2 = y^2 - 2xy + x^2 where x = 1 and y =3
y^2 - 2xy + x^2 = (3)^2 - (2 * 1 * 3) + (1)^2 do not forget PEMDAS
PEMDAS = parenthesis, exponent, multiplication, division, addition, subtraction
y^2 - 2xy + x^2 = 9 - 6 + 1
y^2 - 2xy + x^2 = 4
(y - x)^2 = y^2 - 2xy + x^2 = 4
SHORT METHOD:
(y - x)^2 where x = 1 and y =3
(y - x)^2 = (3 - 1) ^2
(y - x)^2 = (2)^2
(y - x)^2 = 4
Same process for other numbers, good luck!
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Answers & Comments
Answer:
1. m + 5q = 26
2. (y - x)^2 = 4
Step-by-step explanation:
Just substitute
1. m + 5q, where m = 1 and q = 5
m + 5q = 1 + (5*5)
m + 5q = 1 + 25
m + 5q = 26
for number 2, you need to simplify it first then substitute or directly substitute it
LONG METHOD:
(y - x)^2 = y^2 - 2xy + x^2 where x = 1 and y =3
y^2 - 2xy + x^2 = (3)^2 - (2 * 1 * 3) + (1)^2 do not forget PEMDAS
PEMDAS = parenthesis, exponent, multiplication, division, addition, subtraction
y^2 - 2xy + x^2 = 9 - 6 + 1
y^2 - 2xy + x^2 = 4
(y - x)^2 = y^2 - 2xy + x^2 = 4
SHORT METHOD:
(y - x)^2 where x = 1 and y =3
(y - x)^2 = (3 - 1) ^2
(y - x)^2 = (2)^2
(y - x)^2 = 4
Same process for other numbers, good luck!