Answer:
Step-by-step explanation:
(6^2 - 2^2) x (2/3)^-3 + [(6^0 + 7^0 ÷ { 8^0 + (1/3)^0}]
= 32 x (3/2)^3 + [(1 + 1 ÷ { 1 + 1 }]
= 32 x 3^3/2^3 + [ 2/2 ]
= 32 x 27/8 + 1
= 108 + 1
= 109 (ans)
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WE GET
(36-4) x(27/8) + [(1+1) /(2)]
32x27/8 +1
27x4 +1
108+1
109
Answer=109
Answer:
Step-by-step explanation:
(6^2 - 2^2) x (2/3)^-3 + [(6^0 + 7^0 ÷ { 8^0 + (1/3)^0}]
= 32 x (3/2)^3 + [(1 + 1 ÷ { 1 + 1 }]
= 32 x 3^3/2^3 + [ 2/2 ]
= 32 x 27/8 + 1
= 108 + 1
= 109 (ans)