Answer:
Potential energy,U=
4πϵ
0
1
∑
i<j
r
ij
q
i
j
=
12
2
+
23
3
13
Here, q
=q
=q,r
=r
=l
so, U=
l
3q
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Answers & Comments
Answer:
Potential energy,U=
4πϵ
0
1
∑
i<j
r
ij
q
i
q
j
=
4πϵ
0
1
r
12
q
1
q
2
+
4πϵ
0
1
r
23
q
2
q
3
+
4πϵ
0
1
r
13
q
1
q
3
Here, q
1
=q
2
=q
3
=q,r
12
=r
23
=r
13
=l
so, U=
4πϵ
0
1
l
q
2
+
4πϵ
0
1
l
q
2
+
4πϵ
0
1
l
q
2
=
4πϵ
0
1
l
3q
2