Answer:
1. is true because if you plug in -1 into the equation it will be indefinite because we will have 0/0 situation
2. False. y can be the same variable as "a"
3.thus is true if you factor out p^3+q^3 itll he (p+q)^2(p+q) as for the denominator magiging (p+q)^2 the two cancels put which left us with p+q
4.false you can factor out the denominator itll be m^3+1/(-m+1)^2
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Answers & Comments
Answer:
1. is true because if you plug in -1 into the equation it will be indefinite because we will have 0/0 situation
2. False. y can be the same variable as "a"
3.thus is true if you factor out p^3+q^3 itll he (p+q)^2(p+q) as for the denominator magiging (p+q)^2 the two cancels put which left us with p+q
4.false you can factor out the denominator itll be m^3+1/(-m+1)^2