Part II: Problem Solving. Directions: Solve the given problem. Write your answers on the blanks provided.
The width of a rectangle is 11 centimeters less than twice its length. Its area is 40 square centimeters.
Find the dimensions (length and width) of the rectangle.
Representation: (36 – 37) 36. Let be the _______________________ of the rectangle
37. Therefore, _____________________ is the width of the rectangle
Formula/Equation: (38) 38. Area of a rectangle, = ____________________________
Final Answer: (39 – 40) 39. length of rectangle = ______________________
40. width of rectangle = _______________________
The width of a rectangle is 11 centimeters less than twice its length. Its area is 40 square centimeters.
Find the dimensions (length and width) of the rectangle.
Representation: (36 – 37) 36. Let be the _______________________ of the rectangle
37. Therefore, _____________________ is the width of the rectangle
Formula/Equation: (38) 38. Area of a rectangle, = ____________________________
Final Answer: (39 – 40) 39. length of rectangle = ______________________
40. width of rectangle = _______________________
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Answer:
38. 242 square meters
39. 22 cm
40. 11 cm
I do not know 36-37
Make this brainliest answer and give it a heart thank you
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