Answer:
C6H12O6 or (CH2O)6
Explanation:
let n be the number with which empirical formula has to be multiplied with in order to get Molecular formula.
n = [tex]\frac{Molecular weight}{Empirical weight} \\[/tex]
Here, empirical weight (CH2O) = 30
n = 180/30 = 6
Now, just multiply empirical formula with n : (CH2O)6 = C6H12O6
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Verified answer
Answer:
C6H12O6 or (CH2O)6
Explanation:
let n be the number with which empirical formula has to be multiplied with in order to get Molecular formula.
n = [tex]\frac{Molecular weight}{Empirical weight} \\[/tex]
Here, empirical weight (CH2O) = 30
n = 180/30 = 6
Now, just multiply empirical formula with n : (CH2O)6 = C6H12O6