Ek scientist ne ek room mein thermometer rakha. Har ek ghante mein, room ka temperature 10% gir gaya. Agar shuruwat mein room ka temperature 30 degrees Celsius tha, toh 3 ghante baad temperature kitna hoga?
Scientist ne kaha hai ki har ek ghante mein room ka temperature 10% gir raha hai. Iska matlab, agar shuruwat mein room ka temperature \( T_0 \) hai, toh har ghante ke baad woh 90% ho jayega.
Temperature after 1 hour: \( T_1 = 0.90 \times T_0 \)
Temperature after 2 hours: \( T_2 = 0.90 \times T_1 = 0.90 \times 0.90 \times T_0 \)
Temperature after 3 hours: \( T_3 = 0.90 \times T_2 = 0.90 \times 0.90 \times 0.90 \times T_0 \)
Ab humein shuruwat temperature \( T_0 \) diya gaya hai, jo ki 30 degrees Celsius hai. Isko hum calculations mein substitute karte hain:
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Answer:
Scientist ne kaha hai ki har ek ghante mein room ka temperature 10% gir raha hai. Iska matlab, agar shuruwat mein room ka temperature \( T_0 \) hai, toh har ghante ke baad woh 90% ho jayega.
Temperature after 1 hour: \( T_1 = 0.90 \times T_0 \)
Temperature after 2 hours: \( T_2 = 0.90 \times T_1 = 0.90 \times 0.90 \times T_0 \)
Temperature after 3 hours: \( T_3 = 0.90 \times T_2 = 0.90 \times 0.90 \times 0.90 \times T_0 \)
Ab humein shuruwat temperature \( T_0 \) diya gaya hai, jo ki 30 degrees Celsius hai. Isko hum calculations mein substitute karte hain:
\[ T_3 = 0.90 \times 0.90 \times 0.90 \times 30 \]
\[ T_3 = 0.729 \times 30 \]
\[ T_3 = 21.87 \]
Isliye, 3 ghante baad room ka temperature lagbhag 21.87 degrees Celsius hoga.
Explanation:
Verified answer
Answer:
Starting room temperature: 30°C
10 % fall = 30-30*10/100 = 27
In 3 hours = 30-27*3 = -51