Each side of rhombus is 13cm and the length of one diagonal is 24cm. Find the area of the rhombus
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So first we should divide the diagonal now a triangle ABC the angle is 90degree now by Pythagoras theorem (AC)²=(AB)²+(CA)² now we have AC as 13cm n AC=12 so it is (13)²=(12)²+(CA)² 169=144+(CA)² (CA)²=169-144 (CA)²=25 CA=5 so another diagonal =CA×2 =5×2 =10 so Area =½×10×24 =120cm²
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now a triangle ABC
the angle is 90degree
now by Pythagoras theorem
(AC)²=(AB)²+(CA)²
now we have AC as 13cm
n AC=12
so it is
(13)²=(12)²+(CA)²
169=144+(CA)²
(CA)²=169-144
(CA)²=25
CA=5
so another diagonal =CA×2
=5×2
=10
so Area =½×10×24
=120cm²