Video Transcript

this question asked us to write a formula for the given sequence. What we know is that we alternate between positive and negative values. Therefore, each term is multiplied by negative one to the power and minus one. And then we know the numerator. Zahra Old perfect squares therefore were multiplying remote point by n squared. And then lastly, the denominators are one more than end. Therefore, the denominator is simply n plus one or one plus.