Answer:

Therefore, dark brown-reddish fumes of bromine gas are observed at the anode and a greyish-white deposit of lead metal is observed at the cathode.

Explanation:

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[tex]{\huge{\bf{{{\orange {\underbrace{\pink {\mathbb{\: ANSWER}}}}}}}}}[/tex]

[tex]\color{green}{Observation \: At The \: Anode}[/tex]

• Bromine gas is formed after the bromide ions loses electrons.

• Dark brown-reddish fumes of bromine gas are obtained at the anode.

[tex]\color{skyblue}{Observation \: At \: The \: Cathode}[/tex]

• The electrons that bromide ion lost are here accepted by the lead ions.

• As a result greyish-white deposit of lead metal is observed at the cathode.

[tex]{ \color{black}{\boxed{\fcolorbox{lime}{skyblue} { Solution}}}}[/tex]

Therefore, dark brown-reddish fumes of bromine gas are observed at the anode and a greyish-white deposit of lead metal is observed at the cathode.

[tex]\small\bf{\underline{\green{✔verified \: answer }}}[/tex]

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