given:
110 = (3x - 4)(2x)
110 = 6x² - 8x
6x² - 8x - 110 = 0
(3x + 11)(x - 5) = 0
3x + 11 = 0
x - 5 = 0
x = -11/3 or x = 5
r = d/t
r = 110/2(5)
r = 11
Thus, the rate of a car is 11 kph.
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Answers & Comments
given:
110 = (3x - 4)(2x)
110 = 6x² - 8x
6x² - 8x - 110 = 0
(3x + 11)(x - 5) = 0
3x + 11 = 0
x - 5 = 0
x = -11/3 or x = 5
r = d/t
r = 110/2(5)
r = 11
Thus, the rate of a car is 11 kph.