Answer:
if x = 0
y = -3
if x = 1
y = -2
if x = 2
y = 1
the graph will be on 4th quadrant.
please mark as brainliest
[tex]\large\underline{\sf{Solution-}}[/tex]
Given equation is
[tex]\sf \: 4x - 2y - 6 = 0 \\ \\ [/tex]
[tex]\sf \: 2(2x - y - 3) = 0 \\ \\ [/tex]
[tex]\sf \: 2x - y - 3 = 0 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = 2x - 3 \\ \\ [/tex]
Substituting 'x = 0' in the given equation, we get
[tex]\sf \: y = 2 \times 0 - 3 \\ \\ [/tex]
[tex]\sf \: y = 0 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = - 3 \\ \\ [/tex]
Substituting 'x = 1' in the given equation, we get
[tex]\sf \: y = 2 \times 1 - 3 \\ \\ [/tex]
[tex]\sf \: y = 2 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = - 1 \\ \\ [/tex]
Substituting 'x = 2' in the given equation, we get
[tex]\sf \: y = 2 \times 2 - 3 \\ \\ [/tex]
[tex]\sf \: y = 4 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = 1 \\ \\ [/tex]
Substituting 'x = 3' in the given equation, we get
[tex]\sf \: y = 2 \times 3 - 3 \\ \\ [/tex]
[tex]\sf \: y = 6 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = 3 \\ \\ [/tex]
Hᴇɴᴄᴇ,
➢ Pair of points of the given equation are shown in the below table.
[tex]\qquad\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y = 2x - 3 \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf - 3 \\ \\ \sf 1 & \sf - 1 \\ \\ \sf 2 & \sf 1\\ \\ \sf 3 & \sf 3 \end{array}} \\ \end{gathered} \\ \\ [/tex]
➢ Now draw a graph using the points.
➢ See the attachment graph.
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Answers & Comments
Answer:
if x = 0
y = -3
if x = 1
y = -2
if x = 2
y = 1
the graph will be on 4th quadrant.
please mark as brainliest
Verified answer
[tex]\large\underline{\sf{Solution-}}[/tex]
Given equation is
[tex]\sf \: 4x - 2y - 6 = 0 \\ \\ [/tex]
[tex]\sf \: 2(2x - y - 3) = 0 \\ \\ [/tex]
[tex]\sf \: 2x - y - 3 = 0 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = 2x - 3 \\ \\ [/tex]
Substituting 'x = 0' in the given equation, we get
[tex]\sf \: y = 2 \times 0 - 3 \\ \\ [/tex]
[tex]\sf \: y = 0 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = - 3 \\ \\ [/tex]
Substituting 'x = 1' in the given equation, we get
[tex]\sf \: y = 2 \times 1 - 3 \\ \\ [/tex]
[tex]\sf \: y = 2 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = - 1 \\ \\ [/tex]
Substituting 'x = 2' in the given equation, we get
[tex]\sf \: y = 2 \times 2 - 3 \\ \\ [/tex]
[tex]\sf \: y = 4 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = 1 \\ \\ [/tex]
Substituting 'x = 3' in the given equation, we get
[tex]\sf \: y = 2 \times 3 - 3 \\ \\ [/tex]
[tex]\sf \: y = 6 - 3 \\ \\ [/tex]
[tex]\sf\implies \sf \: y = 3 \\ \\ [/tex]
Hᴇɴᴄᴇ,
➢ Pair of points of the given equation are shown in the below table.
[tex]\qquad\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y = 2x - 3 \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf - 3 \\ \\ \sf 1 & \sf - 1 \\ \\ \sf 2 & \sf 1\\ \\ \sf 3 & \sf 3 \end{array}} \\ \end{gathered} \\ \\ [/tex]
➢ Now draw a graph using the points.
➢ See the attachment graph.