1.Draw a line AB=6.8cm. Taking A as center, and radius more than AB,draw arcs on top and bottom of AB
2.Taking A as center, and radius as before,draw arcs on top and bottom of AB
3.Let the point where arcs intersect on top of AB be P.And the point where arcs intersect at the bottom be Q.Join PQ
4.Let PQ intersect AB at the point M.
Thus, line PMQ is the required perpendicular bisector of AB....
Hope it's helpful for you...
So... ❣️Best of luck Babe❣️
Answer:
good evening. how are you
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Answers & Comments
1.Draw a line AB=6.8cm. Taking A as center, and radius more than AB,draw arcs on top and bottom of AB
2.Taking A as center, and radius as before,draw arcs on top and bottom of AB
3.Let the point where arcs intersect on top of AB be P.And the point where arcs intersect at the bottom be Q.Join PQ
4.Let PQ intersect AB at the point M.
Thus, line PMQ is the required perpendicular bisector of AB....
Hope it's helpful for you...
So... ❣️Best of luck Babe❣️
Answer:
good evening. how are you