Answer:
Steps of Construction:
1. Draw a triangle ABC of given dimensions such as AB = BC = CA = 6.5cm
2. Draw a perpendicular bisector of side AB which intersects AB at D.
3. Join C to D.
4. Draw a line parallel to AB through B and C by completing the parallelogram ACQB.
5. From D, construct ∠GDB=45° ( The line cutting BC will be G )
6. The line cuts parallel line through C at E.
7. From E, cut an arc of length DB on the parallel line.
8. Mark the point as F.
9. Join F to B.
10. DBFE is the required parallelogram.
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Verified answer
Answer:
Steps of Construction:
1. Draw a triangle ABC of given dimensions such as AB = BC = CA = 6.5cm
2. Draw a perpendicular bisector of side AB which intersects AB at D.
3. Join C to D.
4. Draw a line parallel to AB through B and C by completing the parallelogram ACQB.
5. From D, construct ∠GDB=45° ( The line cutting BC will be G )
6. The line cuts parallel line through C at E.
7. From E, cut an arc of length DB on the parallel line.
8. Mark the point as F.
9. Join F to B.
10. DBFE is the required parallelogram.
Answer:
Ha ye kr lo pehle....
Mere exams ho gye ab to tuze hi pdhna hai..pdho stanti se...:)